Question

A bag is filled with green and blue marbles. There are 105 marbles in the bag. If there are 9 more green marbles than blue marbles, find the number of green marbles and the number of blue marbles in the bag.

Answer 1

for the blue, just solve

b + b+9 = 105
and then you can get the green

Answer 2

or, as a more Gauss-like method, assume they are half-and-half

(or almost, since there is an odd number)
52+53 = 105
now, since the amounts are separated by 9, rather than 1, just move away 4 in each direction
48+57 = 105

Answer 3

Thanks:)

Answer 4

[AI-generated answer — Explain Bot]

To find the number of green and blue marbles in the bag, let's assign some variables.

Let's say the number of blue marbles is x.

Since there are 9 more green marbles than blue marbles, the number of green marbles can be represented as x + 9.

According to the problem, there are 105 marbles in the bag.

So, the sum of the number of green and blue marbles is x + (x + 9) = 2x + 9.

Since the total number of marbles is given as 105, we can write the equation:

2x + 9 = 105.

To solve this equation:

1. Subtract 9 from both sides:

2x = 105 - 9.

Simplify:

2x = 96.

2. Divide both sides by 2:

x = 96 / 2.

Simplify:

x = 48.

Therefore, there are 48 blue marbles in the bag.

To find the number of green marbles, substitute the value of x we found back into the equation x + 9:

green marbles = 48 + 9 = 57.

So, there are 57 green marbles in the bag.