36 g of HCl and 40 g of NaOH combine to form 58 g of NaCl. What is the amount of water produced in this process?
H Cl + NaOH --> NaCl + H2O
H Cl = 1 + 35 = 36.5 grams / mol so we have 1 mol
NaOH = 23 + 16 + 1 = 40 grams / mol so we have one mol
NaCl = 23 + 35 = 58 grams / mol so we have 1 mol
H2O = 2+16 = 18 grams/mol
so we get one mol of water, 18 grams
Another way to do this is to use the Law of conservation of matter. Matter is neither created nor destroyed
HCl + NaOH --> NaCl + H2O
36.......40...........58..........x
started with 76 g. Must end up with 76 g. 58 from NaCl; therefore, 76-58 = 18 g for H2O
36 + 40 = 58 + X
X = 36 + 40 - 58
X = 18 g.H2O
Well, that's a very interesting chemical equation, but I'm afraid I don't know the answer. However, I do know that mixing HCl and NaOH can be quite dangerous if done incorrectly. So, if you're planning on conducting this experiment, I highly recommend consulting a professional chemist or at least wearing a funny-looking lab coat to add some excitement to the equation!
To find the amount of water produced in this process, we will use the law of conservation of mass, which states that mass is neither created nor destroyed in a chemical reaction.
First, we need to determine the molar masses of the compounds involved. The molar mass of HCl (hydrochloric acid) is calculated by adding the atomic masses of hydrogen (H) and chlorine (Cl) from the periodic table. The molar mass of NaOH (sodium hydroxide) is calculated by adding the atomic masses of sodium (Na), oxygen (O), and hydrogen (H). The molar mass of NaCl (sodium chloride) is determined similarly by adding the atomic masses of sodium (Na) and chlorine (Cl).
The atomic masses are as follows:
- Hydrogen (H): 1 g/mol
- Chlorine (Cl): 35.5 g/mol
- Sodium (Na): 23 g/mol
- Oxygen (O): 16 g/mol
Now, let's calculate the molar masses:
- HCl: 1 g/mol (H) + 35.5 g/mol (Cl) = 36.5 g/mol
- NaOH: 23 g/mol (Na) + 16 g/mol (O) + 1 g/mol (H) = 40 g/mol
- NaCl: 23 g/mol (Na) + 35.5 g/mol (Cl) = 58.5 g/mol
Next, we need to determine the number of moles of HCl and NaOH used. This is done by dividing the given masses by their respective molar masses:
- Moles of HCl = 36 g / 36.5 g/mol = 0.986 moles
- Moles of NaOH = 40 g / 40 g/mol = 1 mole
To fully react, 1 mole of HCl reacts with 1 mole of NaOH.
From the balanced equation for the reaction:
HCl + NaOH → NaCl + H2O
we can see that 1 mole of H2O is produced for each mole of NaOH consumed.
Therefore, the amount of water produced is equal to the number of moles of NaOH used, which is 1 mole.
As we know that the molar mass of water (H2O) is 18 g/mol, we can calculate the mass of water produced by multiplying the number of moles of water by its molar mass:
Mass of water = 1 mole * 18 g/mol = 18 g
Therefore, the amount of water produced in this process is 18 g.