Which statement correctly compares the valence electrons for atoms of francium (Fr) and barium (Ba)?

(1 point)

Francium has more valence electrons, and they are in a higher energy level.

Barium has fewer valence electrons, but they are in a higher energy level.

Barium has more valence electrons, and they are in a higher energy level.

Francium has fewer valence electrons, but they are in a higher energy level.

I think it’s ‘Francium has fewer valance electrons, but they are in a higher energy level’

Since they are on a higher period but has one less valence electron than Barium.

I finished the test, I was correct

Atomic Structure Unit Test 2022

1) A - the number of protons, electrons and neurons
2) B - it is a non-metal.
3) A - atomic number
4) C - low energy alpha particles passing through a field of high mass number particles
5) A - Metals can be hammered into thin sheets, and nonmetals are brittle
6) A - Vanadium
7) C - Silicon
8) A - Hydrogen does not have any neutrons.
9) B - Francium has fewer valence electrons, but they are in a higher energy level.
10) A - They have a full valence electron shell.
11) A - An ionic bond is likely because they will want to give away two valence electrons in order to become stable.
12) B - four
13) A - 2--
14) i wrote, "this ball and stick model has two hydrogen atoms and one oxygen atom, forming H20" (make sure you change up some words)
15) i wrote, "Neon's atomic number is 10, and sodiums atomic number is 11. Neon has an outer shell full of electrons, so it can't react with other elements. Sodium has one more proton and one more electron than neon, so the added electron is in the outside shell, creating a valance electron. Therefore neon is not is not reactive and sodium is very reactive."
16) i didn't do this one so just.. guess the answer lmao

goodluck on ur test :)

@Regal can you help me with the answers?

will upload answers in a few days, hang in there guys !!

The correct statement is: Francium has one valence electron, while barium has two valence electrons.

To determine the number of valence electrons for an atom, you can refer to the electron configuration of the element. Each period in the periodic table represents a different energy level, and the number of electrons in the outermost energy level is the number of valence electrons.

Francium is in period 7 of the periodic table, which means it has seven energy levels. The electron configuration for francium is [Rn] 7s1, indicating that it has one electron in the outermost 7s energy level. Therefore, francium has one valence electron.

Barium is in period 6 of the periodic table, so it has six energy levels. The electron configuration for barium is [Xe] 6s2, indicating that it has two electrons in the outermost 6s energy level. Hence, barium has two valence electrons.

Therefore, the correct statement is: Francium has one valence electron, while barium has two valence electrons.

I don't think it's c. Look at these on the periodic table. Ba is 56 and Fr is 87. Fr has 1 valence electron; Ba has two. Fr is in period 7 while Ba is in period 6. So that single electron in Fr is in a higher energy level than the two in Ba.

B

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(Open Ended)
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I think its see

c

i meant l0l