Question

Find domain and range of

F(x)= root(x^2+4x+3)

Answer 1

√x is defined only for x >= 0

So, you need x^2+4x+3 >= 0
That is x <= -3 or x >= 1
The domain is thus (-∞,-3]U[-1,∞)

since f(x) = (x+2)^2 -1
the range is [-1,∞)