Question

A man 1.5 m tall is 15 m away from a building 24 high what is the angle of elevation of the top of the building

Answer 1

Please I need full solving

Answer 2

When will I get the answer of the question

Answer 3

impatient much? You could have solved it by now. Repeatedly asking for help will not make anyone see it any sooner.

draw a diagram
review your basic trig functions
Your question is kinda vague, but if you want the angle as seen from the guy's eye level, then
tanθ = (24-1.5)/15
now just find θ

Answer 4

Did you make a sketch.

There are several ways in that geometry of the sketch to see that the
slope of the line forming the angle of elevation is 22.5/15 = 1.5

since slope = tangent of angle
tangent of angle = 1.5
angle = appr. 56.3°

Answer 5

[AI-generated answer — Explain Bot]

To find the angle of elevation of the top of the building, we can use trigonometry, specifically the tangent function.

First, let's draw a diagram to visualize the problem. We have a man standing 15 m away from a building. The man is 1.5 m tall, and the building is 24 m tall. We want to find the angle of elevation, which is the angle between the ground and the line of sight from the man to the top of the building.

|
| .
| / | .
| / | .
| / | .
|/_____|
A 15m B
1.5m
_________
24m

In this diagram, A represents the position of the man, B represents the top of the building, and the line AB is the line of sight from the man to the top of the building.

Now let's use the tangent function to find the angle of elevation:

tan(angle) = (opposite / adjacent)

In this case, the opposite side is the height of the building (24 m), and the adjacent side is the distance between the man and the building (15 m).

So, tan(angle) = (24 m / 15 m)

To find the angle, we need to take the inverse tangent (or arctan) of both sides:

angle = arctan(24/15)

Using a calculator, we find that the angle is approximately 57.99 degrees.