Am asking on how a solid sample of lead ii chloride can be prepared using the following reagents dilute nitric acid, dilute hydrochloric acid, and lead carbonate
Dissolve the PbCO3 solid in dilute HNO3 to form Pb(NO)3)2. Add dilute HCl, with stirring, until all of the PbCl2 has pptd. Filter, wash the ppt with dilute HCl followed with DI H2O. Dry the solid in an oven @ 103-105 C until dry (about two hours unless you're preparing gobs of stuff).
I like how Google answers my questions 😄
To prepare a solid sample of lead II chloride using the given reagents, dilute nitric acid, dilute hydrochloric acid, and lead carbonate, you can follow these steps:
1. Start by preparing a solution of dilute hydrochloric acid by adding a desired amount of dilute hydrochloric acid to a container. Remember to follow the appropriate safety precautions while handling acids.
2. Add an excess amount of lead carbonate to the dilute hydrochloric acid solution. The reaction between lead carbonate and hydrochloric acid will produce lead II chloride.
PbCO3(s) + 2HCl(aq) → PbCl2(s) + CO2(g) + H2O(l)
3. Stir the mixture well to ensure complete reaction. The lead II chloride will form as a solid precipitate, while carbon dioxide gas is released and evaporates into the air.
4. Allow the mixture to stand undisturbed for some time to allow the solid lead II chloride to settle.
5. Filter the mixture using filter paper and a funnel to separate the precipitate (lead II chloride) from the liquid (aqueous hydrochloric acid solution).
6. Wash the solid lead II chloride with distilled water to remove any impurities or remaining chloride ions.
7. After washing, allow the solid to dry either by air drying or using a desiccator.
Following these steps will help you prepare a solid sample of lead II chloride using the provided reagents.
To prepare a solid sample of lead II chloride (PbCl2), you will need the following reagents: dilute nitric acid (HNO3), dilute hydrochloric acid (HCl), and lead carbonate (PbCO3).
Here's the step-by-step process to prepare the solid sample of lead II chloride:
1. Start by dissolving lead carbonate (PbCO3) in dilute nitric acid (HNO3). The reaction that occurs is as follows:
PbCO3 + 2HNO3 → Pb(NO3)2 + CO2 + H2O
2. The lead carbonate reacts with the nitric acid, forming lead nitrate (Pb(NO3)2), carbon dioxide (CO2), and water (H2O). The carbon dioxide will escape as a gas during this process.
3. After the reaction is complete, you will have a solution of lead nitrate (Pb(NO3)2) and excess nitric acid (HNO3). Make sure all the lead carbonate has dissolved by stirring the solution.
4. Next, add dilute hydrochloric acid (HCl) to the lead nitrate solution. The following reaction will occur:
Pb(NO3)2 + 2HCl → PbCl2 + 2HNO3
5. Lead nitrate reacts with the hydrochloric acid, forming solid lead II chloride (PbCl2), nitric acid (HNO3), and a solution of hydrochloric acid (HCl).
6. As the lead II chloride forms, it will precipitate out of the solution as a white solid. Allow the solution to sit undisturbed for some time, allowing the precipitate to settle.
7. Once the precipitate has settled, carefully decant the liquid (HNO3 and HCl) from the solid lead II chloride.
8. Finally, wash the lead II chloride with distilled water to remove any remaining impurities and residues from the reaction.
After following these steps, you should have a solid sample of lead II chloride (PbCl2) ready for use or further analysis. Make sure to handle all the reagents and products with proper safety precautions as they can be hazardous.