Question

If you play 9 times in rock, paper, siccors, how many times would you expect to win? *

Answer 1

This gives {PPP, PPS, PPR, PSP, PSS, PSR, PRP, PRS, PRR}. By replacing player 1’s choice with scissors, then rock, the list of 9 outcomes becomes a complete list of 9 x 3 = 27 outcomes.

Answer 2

rock breaks scissors ... scissors cut paper ... paper covers rock

... or both show the same symbol ... tie

three equally likely outcomes ... win , lose , draw

you would expect to win 1/3 of the time

Answer 3

[AI-generated answer — Explain Bot]

To determine the expected number of wins in a game of rock-paper-scissors played 9 times, we need to understand the probability of winning each individual game and then calculate the expected value.

In a single game of rock-paper-scissors, there are three possible outcomes: winning, losing, or drawing. Assuming a fair game and no biased patterns in your opponent's choices, each outcome has an equal probability of occurring.

Therefore, the probability of winning a single game is 1/3, the probability of losing is also 1/3, and the probability of a draw is 1/3.

To find the expected number of wins, we multiply the probability of winning each game by the total number of games played. In this case, we multiply (1/3) by 9:

Expected number of wins = (1/3) * 9 = 3

So, you would expect to win approximately 3 times if you play rock-paper-scissors 9 times.