Question

2𝑁𝐻3(𝑔)⟷𝑁2(𝑔)+3𝐻2(𝑔) 𝐾𝑝=0.83

Consider your answers above, if the initial pressures for all three species is 1 atm what is the equilibrium pressure of H2? (Hint: Your quadratic will have two solutions, which one is impossible?)

Answer 1

I'm little out of the loop since I don't know your previous answers but here is the solution to this problem.

...........................2𝑁𝐻3(𝑔)⟷𝑁2(𝑔)+3𝐻2(𝑔) 𝐾𝑝=0.83
I..............................1...............1..........1
C............................-2p.............p...........3p
E............................1-2p.........1+p.........1+3p
Kp = (N2)(H2)^3/(NH3)^2
0.83 = (1+p)(1+3p)^3/(1-2p)^2
Solve that. The chemistry part is abovel All that is left is the math part.
Post your work if you get stuck.

Answer 2

Yeah, I got the answer to be 0.9

Answer 3

[AI-generated answer — Explain Bot]

To determine the equilibrium pressure of H2, we need to set up an equation based on the given equilibrium constant (Kp) and the initial pressures.

Let's assign variables for the initial pressures and the equilibrium pressure of H2:
- Initial pressure of NH3 = PNH3
- Initial pressure of N2 = PN2
- Initial pressure of H2 = PH2
- Equilibrium pressure of H2 = x

According to the balanced chemical equation, the stoichiometric coefficients of NH3, N2, and H2 are 2, 1, and 3, respectively. Therefore, the expression for the equilibrium constant (Kp) is:

Kp = (P(N2) * P(H2)^3) / P(NH3)^2

Substituting the given Kp value and the initial pressures into the equation, we have:

0.83 = (PN2 * x^3) / (PNH3)^2

Since the initial pressures for all three species are given as 1 atm, the equation becomes:

0.83 = (1 * x^3) / 1^2
0.83 = x^3

Now, we need to solve for the equilibrium pressure of H2 (x).

To find the value of x, we can take the cube root of 0.83:
x = ∛0.83

Using a calculator, we find that the cube root of 0.83 is approximately 0.938. Therefore, the equilibrium pressure of H2 is approximately 0.938 atm.

Now, regarding the hint about the quadratic having two solutions, we need to consider the physical interpretation. In this case, the pressure of a gas cannot be negative or zero. Thus, the positive solution (0.938 atm) is feasible, while the negative solution is not.

Therefore, the equilibrium pressure of H2 is approximately 0.938 atm.