Question

1.8 mol HCl and 3.3 mol NaOH react according to the equation

Answer 1

1.8 mol HCl and 3.3 mol NaOH react accord- ing to the equation

HCl + NaOH −→ NaCl + H2O .
Calculate the amount in moles of NaCl formed.
Answer in units of mol.

Answer 2

Here's a similar problem:

www.jiskha.com/questions/674647/1-9-mol-hcl-and-3-8-mol-naoh-react-according-to-the-equation-hcl-naoh-nacl-h2o

Answer 3

This is a limiting reagent (LR) problem. You know you have a LR problem when an amount for more than one reactant is given.

HCl + NaOH −→ NaCl + H2O .
Use the coefficients to tell you the following:
1.8 mols HCl will form 1.8 mols NaCl given an excess of NaOH.
3.3 mols NaOH will form 3.3 mols NaCl given an excess of HCl.
Of those two scenarios you will form 1.8 mols NaCl; i.e., the smaller amount of substance formed is always the winner in LR problems.

Answer 4

[AI-generated answer — Explain Bot]

To determine the products of the reaction between 1.8 mol of HCl and 3.3 mol of NaOH, we need to first write the balanced equation for the reaction.

The balanced equation for the reaction between HCl and NaOH is:

HCl + NaOH → NaCl + H2O

From the balanced equation, we can see that one mole of HCl reacts with one mole of NaOH to produce one mole of NaCl and one mole of H2O.

Given that we have 1.8 mol of HCl and 3.3 mol of NaOH, we can determine the limiting reactant, which is the reactant that is completely consumed and limits the amount of product formed.

The stoichiometry of the reaction tells us that the mole ratio of HCl to NaOH is 1:1. Therefore, if there is an excess of HCl or NaOH, one of them will be left over.

To determine the limiting reactant, we compare the number of moles of HCl and NaOH. In this case, we have 1.8 mol of HCl and 3.3 mol of NaOH. Since the mole ratio is 1:1, if we have equal moles of HCl and NaOH, we will use up all of the reactants.

Since we have more moles of NaOH (3.3 mol) than HCl (1.8 mol), HCl is the limiting reactant. This means that HCl will be completely consumed, and NaOH will be left over.

To determine the amount of product formed, we look at the mole ratio between the limiting reactant (HCl) and the product (NaCl). From the balanced equation, we see that the mole ratio of HCl to NaCl is also 1:1.

Since we have 1.8 mol of HCl, we will form 1.8 mol of NaCl.

To summarize, when 1.8 moles of HCl and 3.3 moles of NaOH react, all of the HCl will be consumed, and we will obtain 1.8 moles of NaCl as the product.