Determine two points on the graph of the parabola other than the vertex and the x- and y-intercepts. y=-2x^2+3
pick any two values for x, such as -1 and +1
calculate y for each.
To find two points on the graph of the parabola y = -2x^2 + 3, we can choose any two x-values and then find the corresponding y-values by substituting them into the equation.
Let's choose two x-values: x = 1 and x = -1.
For x = 1:
y = -2(1)^2 + 3
y = -2 + 3
y = 1
So, when x = 1, y = 1. Therefore, the point (1, 1) lies on the graph of the parabola.
For x = -1:
y = -2(-1)^2 + 3
y = -2 + 3
y = 1
So, when x = -1, y = 1. Therefore, the point (-1, 1) lies on the graph of the parabola.
Hence, the two points on the graph of the parabola y = -2x^2 + 3, other than the vertex and the x- and y-intercepts, are (1, 1) and (-1, 1).
To determine two points on the graph of the parabola y = -2x^2 + 3, we can choose any x-values and substitute them into the equation to find the corresponding y-values. Here's how you can do it:
1. Choose an arbitrary value for x. Let's say we choose x = 1.
2. Substitute the chosen x-value into the equation: y = -2(1)^2 + 3. Simplify this to get y = -2 + 3 = 1.
3. So, when x = 1, y = 1. We have one point: (1, 1).
Now, let's choose another value for x. Let's say we choose x = -2.
4. Substitute the chosen x-value into the equation: y = -2(-2)^2 + 3. Simplify this to get y = -2(4) + 3 = -8 + 3 = -5.
5. So, when x = -2, y = -5. We have another point: (-2, -5).
Therefore, two points on the graph of the parabola y = -2x^2 + 3, other than the vertex and x- and y-intercepts, are (1, 1) and (-2, -5).