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A car of mass 600 kg is moving at a speed of 20 m/s.it collides with a stationary car of mass 900 kg.if the first car bounces back at 4 m/s,at what speed does the second car move after the collusion?

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8 answers
  1. conserve momentum.
    600*20 + 900*0 = 600(-4) + 900v

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  2. Jigjiga

    1995

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  3. v=600*20-600*(-4)/900
    =16

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  4. 50.6

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  5. (600kg*20m/s)+(900kg*0m/s)=[600kg*(-4m/s)]+900kg V2
    12,000kgm/s + 0 = -2400kgm/s + (900kg)V2
    12,000kgm/s + 2400kgm/s = 900kg V2
    14,400kgm/s = 900kg V2
    v2 = 14,400kgm/s / 900kg
    v2 = 144m/s / 9
    v2 = 16m/s

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  6. sup dupie

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  7. I LIKE PHYSICS

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  8. Nati man

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