Question

the sum of three consecutive numbers all 36 find them

Answer 1

11, 12, 13

x + x + 1 + x + 2 = 36
3x + 3 = 36
3x = 36 - 3
3x = 33
x = 11
x + 1 = 12
x + 2 = 13

Answer 2

Answer and Explanation:

Three consecutive integers whose sum is 36 are 11, 12, and 13.

Answer 3

[AI-generated answer — Explain Bot]

To find three consecutive numbers with a sum of 36, you can set up the equation as follows:

Let's assume the first number is 'x'. So the next two consecutive numbers will be 'x+1' and 'x+2'.

The sum of these three numbers can be calculated by adding them together:

x + (x+1) + (x+2) = 36

Now, let's simplify the equation:

3x + 3 = 36

Next, we can subtract 3 from both sides of the equation:

3x = 36 - 3
3x = 33

To isolate 'x', divide both sides of the equation by 3:

x = 33/3
x = 11

So, the first number is 11. The next two consecutive numbers are 12 and 13, respectively.

Therefore, the three consecutive numbers whose sum is 36 are 11, 12, and 13.