since 1A = 1C/s,
6.01mC/2.38s = 2.252 mC/s = 2.252 mA
cross-sectional area of a wire in 2.38 s.
What is the current in the wire?
Answer in units of mA.
6.01mC/2.38s = 2.252 mC/s = 2.252 mA
Okay, dividing 6.01 mC by 2.38 s gives us a current of 2.523699 mC/s.
However, we need to convert that to milliamperes (mA). Since 1 A (ampere) is equal to 1000 mA, our final answer is approximately 2.52 mA.
Voila! The current in the wire is approximately 2.52 mA. Keep those electrons flowing!
Current (I) = Charge (Q) / Time (t)
Given that the total charge is 6.01 mC and the time is 2.38 s, we can substitute these values into the formula to find the current:
I = 6.01 mC / 2.38 s
To convert milliCoulombs (mC) to Coulombs (C), we multiply by 10^-3:
I = (6.01 mC * 10^-3) / 2.38 s
Simplifying the calculation:
I = 6.01 * 10^-3 C / 2.38 s
Now, to convert the result to milliamperes (mA), we can use the fact that 1 A (Ampere) is equal to 1000 mA, so:
I = (6.01 * 10^-3 C / 2.38 s) * (1000 mA / 1 A)
Simplifying the calculation:
I = (6.01 * 10^-3 * 1000) / 2.38 mA
Evaluating the expression:
I = 60.1 / 2.38 mA
I ≈ 25.21 mA
Therefore, the current in the wire is approximately 25.21 mA.
I = Q / t
Where:
I = current (in Amperes)
Q = total charge (in Coulombs)
t = time (in seconds)
Given:
Q = 6.01 mC (milliCoulombs)
t = 2.38 s
But since the question asks for the answer in mA (milliamperes), we need to convert the units accordingly.
1 A = 1000 mA
So, 1 C = 1000 mC
Converting the units of charge:
Q = 6.01 mC * (1 C / 1000 mC) = 0.00601 C
Now we can substitute the values into the formula to find the current:
I = 0.00601 C / 2.38 s
I ≈ 0.002526 A
Finally, to convert the current to mA:
I = 0.002526 A * (1000 mA / 1 A)
I ≈ 2.526 mA
Therefore, the current in the wire is approximately 2.526 mA.