Write a balanced equation for the combustion of acetylene (C2H2). If a reaction consumes 15.9 L of acetylene, how many mol of carbon dioxide are produced? (Acetylene has a density of 1.097 g/L.)
2C2H2 + 5O2 ==> 4CO2 + 2H2O
grams C2H2 = volume x density = 15.9 L x 1.097 g/L = 17.4 g
mols = g/molar mass = 17.4/26 = 0.669
That will give you 2*669 = ? mols CO2
Post your work if you get stuck.
To write a balanced equation for the combustion of acetylene (C2H2), we need to know the reactants involved and the products formed. In this case, acetylene reacts with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O).
The balanced equation for the combustion of acetylene is:
2 C2H2 + 5 O2 → 4 CO2 + 2 H2O
Now, to determine the number of moles of carbon dioxide produced when 15.9 L of acetylene is consumed, we need to use the given density of acetylene.
Density is defined as mass divided by volume:
Density = mass / volume
Given that the density of acetylene is 1.097 g/L, and the volume of acetylene consumed is 15.9 L, we can calculate the mass of acetylene using the formula:
mass = density × volume
mass = 1.097 g/L × 15.9 L = 17.47 g
Next, we need to convert the mass of acetylene to moles. To do this, we need the molar mass of acetylene, which is calculated using the atomic masses of carbon (C) and hydrogen (H).
The molar mass of carbon is 12.01 g/mol, and the molar mass of hydrogen is 1.01 g/mol. Since there are two carbon atoms and two hydrogen atoms in each molecule of acetylene (C2H2), we can calculate the molar mass as follows:
Molar mass of acetylene = 2 × (molar mass of carbon) + 2 × (molar mass of hydrogen)
= 2 × 12.01 g/mol + 2 × 1.01 g/mol
= 26.04 g/mol
Now we can convert the mass of acetylene to moles:
moles of acetylene = mass / molar mass
= 17.47 g /26.04 g/mol
=0.671 mol
According to the balanced equation, the stoichiometric ratio between acetylene and carbon dioxide is 2:4. Therefore, for every 2 moles of acetylene, we have 4 moles of carbon dioxide.
So, to find the number of moles of carbon dioxide produced, we can use the following calculation:
moles of carbon dioxide = (moles of acetylene) × (4 moles of carbon dioxide / 2 moles of acetylene)
= 0.671 mol × (4/2)
= 1.342 mol
Therefore, when 15.9 L of acetylene is consumed, 1.342 mol of carbon dioxide is produced.