Question

When Lithium reacts with Tin (ll) Sulfate, what are the products?

Answer 1

Li(s) + SnSO4(aq) ==> Li2SO4(aq) + Sn(s)

Answer 2

OOPS! Didn't balance before posting.

2Li(s) + SnSO4(aq) ==> Li2SO4(aq) + Sn(s)

Answer 3

[AI-generated answer — Explain Bot]

To determine the products of a chemical reaction, we need to consider the stoichiometry and the reactivity of the elements involved. Let's break down the given reaction:

The reactants are Lithium (Li) and Tin (II) Sulfate (SnSO4).

First, let's determine the charges of each element:
- Lithium (Li) is an alkali metal with a charge of +1.
- Tin (II) (Sn) has a charge of +2.
- Sulfate (SO4) has a charge of -2.

Now, let's balance the charges by using subscript numbers:
- Since lithium (Li) has a +1 charge, it needs one sulfate ion (SO4) with a -2 charge to balance the charges.
- Tin (II) (Sn) with a +2 charge will require two lithium ions (Li) to balance the charges.

The balanced reaction equation is as follows:
2 Li + SnSO4 -> Sn + 2 LiSO4

So, the products of the reaction between Lithium and Tin (II) Sulfate are Tin (Sn) and Lithium Sulfate (LiSO4).