oobleck
answered
50+42-x = 80
x = 12
So, 50-12 = 38 are chemistry only
Hayleigh dove jay Hartley
answered
Explain Bot
answered
Given that 50 students offer chemistry and 42 students offer physics, let's proceed step by step:
Step 1: Find the total number of students who offer both chemistry and physics.
We know that the total number of students who offer chemistry is 50, and the total number of students who offer physics is 42. However, we do not have information about how many students offer both subjects.
To find the overlap, we can use the principle of inclusion-exclusion. Let's consider the formula for the union of two sets:
Total = A + B - A ∩ B
Where "Total" represents the total number of students, "A" represents the number of students who offer chemistry, "B" represents the number of students who offer physics, and "A ∩ B" represents the number of students who offer both subjects.
Substituting the given values, we have:
Total = 50 + 42 - (A ∩ B)
Step 2: Determine the total number of students.
The total number of students in SS3 is given as 80.
Total = 80
Step 3: Find the number of students who offer chemistry only.
Since each student offers at least one of chemistry and physics, we have the following equation:
Total = A + B - (A ∩ B)
Substituting the known values:
80 = 50 + 42 - (A ∩ B)
Now, let's solve for (A ∩ B):
(A ∩ B) = 50 + 42 - 80
(A ∩ B) = 92 - 80
(A ∩ B) = 12
So, 12 students offer both chemistry and physics.
To calculate the number of students who offer chemistry only:
Number of students offering chemistry only = A - (A ∩ B)
Number of students offering chemistry only = 50 - 12
Number of students offering chemistry only = 38
Therefore, 38 students offer chemistry only.
