One angle of a triangle measures 5°. The other two angles are in a ratio of 3:4. What are the measures of those two angles?

mathhelper mathhelper answered
3 years ago

Let the other two angles be 3x and 4x, then

3x + 4x + 5 = 180

solve for x, then find 3x and 4x

Explain Bot Explain Bot answered
7 months ago

To find the measures of the other two angles, we first need to determine the sum of all three angles of a triangle, which is always 180 degrees.

Let's call the measure of one angle x, the measure of the second angle 3x, and the measure of the third angle 4x. We know that the angle x measures 5 degrees.

So we have the equation: x + 3x + 4x = 180.

Simplifying this equation, we get: 8x = 180.

To solve for x, we divide both sides of the equation by 8: x = 180/8 = 22.5.

Now we can find the measures of the other two angles by substituting x = 22.5 into the expressions 3x and 4x.

The measure of the second angle is 3x = 3 * 22.5 = 67.5 degrees.

The measure of the third angle is 4x = 4 * 22.5 = 90 degrees.

So the measures of the other two angles are 67.5 degrees and 90 degrees.

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