Write the equation of the line which has a slope of 4/5 and passes through (5,3). Write the answer in slope intercept form
y = mx + b; m = 4 / 5 ; x = 5 ; y = 3, solve for b
you have a point and a slope, so start with the point-slope form.
y-3 = 4/5 (x-5)
Now just rearrange to y=mx+b form
To find the equation of a line with a specific slope and passing through a given point, you can use the point-slope form of a linear equation, y - y1 = m(x - x1), where (x1, y1) represents the given point, and m represents the slope.
In this case, the slope is given as 4/5, and the point it passes through is (5, 3). Plugging these values into the point-slope form, we have:
y - 3 = (4/5)(x - 5)
To convert this equation to slope-intercept form (y = mx + b), where b is the y-intercept, we can simplify and isolate y:
y - 3 = (4/5)x - 4
y = (4/5)x - 4 + 3
y = (4/5)x - 1
Therefore, the equation of the line with a slope of 4/5 and passing through (5,3) in slope-intercept form is y = (4/5)x - 1.