The manager of a snack bar buys bottled water in packs of 35 and candy bars in packs of 20. Then, she sells the items individually. Yesterday, she bought the same number of water bottles as candy bars to sell at the snack bar. If she bought the lowest number of items possible, how many packs of each item did she buy?
5 packs of bottled water and 5 packs of candy bars
4 packs of bottled water and 7 packs of candy bars
8 packs of bottled water and 14 packs of candy bars
20 packs of bottled water and 35 packs of candy bars
4 packs of bottled water and 7 packs of candy bars
ttthnx tyyyssmm
To find the answer, we need to determine the common number of water bottles and candy bars that the manager bought. Let's start by finding the least common multiple (LCM) of 35 and 20, which will give us the minimum quantity the manager bought.
The LCM of 35 and 20 is 140. This means that the manager bought at least 140 items in total.
Since the manager bought the same number of water bottles as candy bars, we need to divide 140 by 2 to find the quantity of each item.
140 divided by 2 is 70. So, the manager must have bought a total of 70 bottles of water and 70 candy bars.
Now, let's check which answer choice matches the quantity of items.
- 5 packs of bottled water (5 x 35 = 175) and 5 packs of candy bars (5 x 20 = 100) do not add up to a total of 140.
- 4 packs of bottled water (4 x 35 = 140) and 7 packs of candy bars (7 x 20 = 140) do add up to a total of 140.
- 8 packs of bottled water (8 x 35 = 280) and 14 packs of candy bars (14 x 20 = 280) exceed the minimum total of 140.
- 20 packs of bottled water (20 x 35 = 700) and 35 packs of candy bars (35 x 20 = 700) also exceed the minimum total of 140.
Therefore, the correct answer is 4 packs of bottled water and 7 packs of candy bars.