Question

solve 3x+5y=47 and 2x+3y=29

Answer 1

3x+5y=47

2x+3y=29

9x+15y = 141
10x+15y = 145
subtract to get
x = 4
so y=7

Answer 2

3x+2x+5y-3y=47+29 therefore 5x=76 x=76/5

Answer 3

[AI-generated answer — Step-by-Step Bot]

To solve this system of equations:

Equation 1: 3x + 5y = 47
Equation 2: 2x + 3y = 29

We can use either the substitution method or the elimination method. Let's use the elimination method in this case.

Step 1: Multiply both sides of Equation 1 by 2, and multiply both sides of Equation 2 by 3 to make the coefficients of x in both equations the same.

Equation 3: 6x + 10y = 94
Equation 4: 6x + 9y = 87

Step 2: Subtract Equation 4 from Equation 3 to eliminate x.

(6x + 10y) - (6x +9y) = 94 - 87
6x - 6x + 10y - 9y = 7
y = 7

Step 3: Substitute the value of y into either Equation 1 or Equation 2 to solve for x. Let's use Equation 1.

3x + 5(7) = 47
3x + 35 = 47
3x = 47 - 35
3x = 12
x = 12/3
x = 4

So, the solution to the system of equations is x = 4 and y = 7.

Answer 4

[AI-generated answer — Explain Bot]

To solve the system of equations:

1) 3x + 5y = 47
2) 2x + 3y = 29

There are multiple ways to solve this system of equations, but one common method is using the method of substitution. Here's how you can do it:

Step 1: Solve one equation for one variable in terms of the other variable. Let's solve equation 2 for x:
2x + 3y = 29
2x = 29 - 3y
x = (29 - 3y) / 2

Step 2: Substitute the expression for x (from step 1) into the other equation. We'll substitute (29 - 3y) / 2 for x in equation 1:
3x + 5y = 47
3((29 - 3y) / 2) + 5y = 47 (substituting x)
(87 - 9y) / 2 + 5y = 47
(87 - 9y) + 10y = 94 (multiplying both sides by 2 to get rid of the denominator)
87 + y = 94
y = 94 - 87
y = 7

Step 3: Substitute the value of y (from step 2) back into one of the original equations to find the value of x. Let's use equation 2:
2x + 3y = 29
2x + 3(7) = 29
2x + 21 = 29
2x = 29 - 21
2x = 8
x = 8 / 2
x = 4

Therefore, the solution to the system of equations is x = 4 and y = 7.