(Take g= 10m/s2 weight of 1g mass =0.01N)
Calculate the weight of a stone of mass 10kg and density 10000km/m3 when it totally immersed in water.
A) 10N
B) 100N
c) 1000N
D) 0.01N
E) 0.001N
that will be the wight of the stone 10kg*10m/s^2
The volume of the stone is, as usual, mass/density. Multiply that by the density of water * g.
Subtract the weight of water displaced from the weight of the stone.
I need the solving
10N
To calculate the weight of a stone when it is totally immersed in water, we will need to use the formula:
Weight = mass x gravitational acceleration
Given:
Gravitational acceleration (g) = 10 m/s^2
Mass (m) = 10 kg
First, let's find the volume of the stone:
Density = mass / volume
Rearranging the formula, we get:
Volume = mass / density
Given:
Density (ρ) = 10000 kg/m^3
Mass (m) = 10 kg
Volume = 10 kg / 10000 kg/m^3 = 0.001 m^3
When the stone is completely immersed in water, it will experience an upthrust equal to the weight of the water displaced. This buoyant force will act in the opposite direction to the weight of the stone. Therefore, the apparent weight of the stone will be:
Apparent Weight = Weight - Buoyant Force
Buoyant Force = weight of the water displaced
The weight of the water displaced can be obtained using the formula:
Weight of water displaced = density of water x volume of the stone x gravitational acceleration
Given:
Density of water (ρw) = 1000 kg/m^3
Volume of the stone = 0.001 m^3
Gravitational acceleration (g) = 10 m/s^2
Weight of water displaced = 1000 kg/m^3 x 0.001 m^3 x 10 m/s^2 = 10 N
Now, we can find the apparent weight of the stone:
Apparent Weight = Weight - Buoyant Force
Apparent Weight = 10 N - 10 N = 0 N
Therefore, the weight of the stone when it is totally immersed in water is 0 N.
So, the correct answer is option D) 0.01N.