60 km/hr * 1000m/km * 1hr/3600s = 16.67 m/s
a = (80-16.67)/20 = 3.17 m/s^2
This is the slope of the graph of the velocity
a = (80-16.67)/20 = 3.17 m/s^2
This is the slope of the graph of the velocity
Given: Car's initial velocity (v1) = 60 km/hr
Car's final velocity (v2) = 80 m/s
Time (t) = 20 seconds
Step 1: Convert initial velocity from km/hr to m/s.
To do this, we use the conversion factor: 1 km/hr = 0.27778 m/s
60 km/hr * 0.27778 m/s = 16.66666 m/s ≈ 16.67 m/s
So, the car's initial velocity (v1) is approximately 16.67 m/s.
Step 2: Plot the points on the graph.
The first point will be (0, 16.67) since at the start time (t = 0 seconds), the car's velocity is 16.67 m/s.
The second point will be (20, 80) since at 20 seconds, the car's velocity increased to 80 m/s.
Step 3: Connect the two points with a straight line.
This straight line represents the speed against time graph.
The graph will have time (t) on the x-axis and speed (v) on the y-axis.