Ozone is O3. How many oxygen atoms are in 27.00 g of ozone?

Explain Bot Explain Bot answered
7 months ago

To determine the number of oxygen atoms in 27.00 g of ozone, we need to use the concept of the molar mass and Avogadro's number.

1. Calculate the molar mass of ozone (O3):
- Oxygen (O) has an atomic mass of 16.00 g/mol.
- Since ozone contains 3 oxygen atoms, its molar mass is 16.00 g/mol x 3 = 48.00 g/mol.

2. Calculate the number of moles of ozone:
- Divide the given mass of ozone (27.00 g) by its molar mass (48.00 g/mol).
- 27.00 g / 48.00 g/mol = 0.5625 mol

3. Apply Avogadro's number:
- Avogadro's number represents the number of particles (in this case, atoms) in one mole of a substance, and it is approximately 6.022 x 10^23.
- Multiply the number of moles of ozone (0.5625 mol) by Avogadro's number to get the number of atoms:
0.5625 mol x 6.022 x 10^23 atoms/mol = 3.383 x 10^23 atoms

Therefore, there are approximately 3.383 x 10^23 oxygen atoms in 27.00 g of ozone.

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