A work of 30 joules is done transferring 5mili Coulombs of charge from a point B to a point A in an electric field field . Find the potential difference between A and B
Yeah!!!
V = potential energy per unit charge
Q V = 30 Joules
5 * 10^-3 * V = 30
V = 6,000 volts (good grief ! )
To find the potential difference between points A and B, we can use the equation:
Potential difference (V) = Work done (W) / Charge (Q)
First, we need to convert the charge from milli Coulombs to Coulombs. Since 1 milli Coulomb is equal to 0.001 Coulombs, the charge Q will be 5 * 0.001 Coulombs = 0.005 Coulombs.
Now we can substitute the values into the formula:
Potential difference (V) = 30 joules / 0.005 Coulombs
Calculating this:
V = 30 / 0.005
V = 6000 volts
Therefore, the potential difference between points A and B is 6000 volts.
To find the potential difference between point A and point B, we need to use the formula:
Potential difference (V) = Work done (W) / Charge (Q)
Given:
Work done (W) = 30 joules
Charge (Q) = 5 milliCoulombs = 5 × 10^(-3) Coulombs
First, let's convert the charge from milliCoulombs to Coulombs:
5 milliCoulombs = 5 × 10^(-3) Coulombs
Now we can substitute the values into the formula:
Potential difference (V) = 30 joules / (5 × 10^(-3) Coulombs)
Simplifying:
Potential difference (V) = 30 / (5 × 10^(-3) Coulombs)
= 30 / 0.005 Coulombs
= 6000 Volts
Therefore, the potential difference between point A and point B is 6000 Volts.