How many grams of acetic acid (C₂H₄O₂) would you use to make 10 L of a 0.1 M aqueous solution of acetic acid? (Note: The atomic masses, in daltons, are approximately 12 for carbon, 1 for hydrogen, and 16 for oxygen.)
10 L of 0.1mol/liter = 1 mol of it
C₂H₄O₂ --> 2*12 + 4*1 + 2*16
= 24 + 4 + 32 = 60 grams / mol
Answer: 60grams
The previous anonymous had it right.
i did XD
Ms.Sue u IMPASTA
no u cant
BC IM SMARRRT
thank you anonymous
i am not cheating i am studying and when i dont know how to solve something i ask for help
To find the number of grams of acetic acid needed, we need to use the formula:
Mass (g) = molar concentration (mol/L) * volume (L) * molar mass (g/mol)
First, we need to calculate the number of moles of acetic acid needed. The molar concentration is given as 0.1 M, which means there are 0.1 moles of acetic acid per liter.
Number of moles of acetic acid = molar concentration * volume
= 0.1 mol/L * 10 L
= 1 mol
To convert moles to grams, we need to know the molar mass of acetic acid (C₂H₄O₂).
Molar mass of acetic acid (C₂H₄O₂) = (2 * atomic mass of carbon) + (4 * atomic mass of hydrogen) + (2 * atomic mass of oxygen)
= (2 * 12.01 g/mol) + (4 * 1.01 g/mol) + (2 * 16.00 g/mol)
= 60.05 g/mol
Now we can calculate the mass of acetic acid needed:
Mass (g) = number of moles * molar mass
= 1 mol * 60.05 g/mol
= 60.05 g
Therefore, you would need to use 60.05 grams of acetic acid to make 10 L of a 0.1 M aqueous solution of acetic acid.