Iḿ doing a sensitivity analysis in the contants of the constraints
3+4y=40+h
2x+1y=20
2x+3y=60
I need to solve for x ....I know what to do later...I have to solve for y and then I have to solve for h in terms of X and Y..
so I just need you to help me solve for x
thanks
subtract #2 from #3 and you have
2y = 40
y = 20
Looks like x=0
subtract Eq3 fr0m Eq2:
2x+y = 20
2x+3y = 60
Diff:-2y = -40
Y = 20.
In Eq2, replace y with 20 and solve for x:
2x+20 = 20
X = 0.
In Eq1, replace y with 20 and solve for h:
3+4*20 = 40+h
h =
To solve for x in the given system of equations:
1. Start by rearranging the equations to isolate the x term.
Equation 2: 2x + y = 20 => 2x = 20 - y => x = (20 - y) / 2
2. Substitute this expression for x into the other equations to eliminate x.
Equation 1: 3 + 4y = 40 + h => 4y = 40 + h - 3 => 4y = 37 + h => y = (37 + h) / 4
Equation 3: 2x + 3y = 60 => 2[(20 - y) / 2] + 3y = 60 => 20 - y + 3y = 60 => 2y = 40 => y = 20
3. Substitute the value of y into equation 2 to find the value of x.
x = (20 - y) / 2 => x = (20 - 20) / 2 => x = 0 / 2 => x = 0
So, the solution to the system of equations is x = 0.