a(3-(-2))=-2(-2)+b
5a = 4+b
So now finish it off
-9 -5 -1 5 9
a= b=
5a = 4+b
So now finish it off
a(3 - x) = -2x + b
Replacing x with -2, we get:
a(3 - (-2)) = -2(-2) + b
Simplifying further:
a(3 + 2) = 4 + b
a(5) = 4 + b
5a = 4 + b
Now, let's look at the given options for the value of a and b:
-9, -5, -1, 5, 9
We'll substitute each option and see which values satisfy the equation:
For a = -9:
5(-9) = 4 + b
-45 = 4 + b
b = -45 - 4
b = -49
For a = -5:
5(-5) = 4 + b
-25 = 4 + b
b = -25 - 4
b = -29
For a = -1:
5(-1) = 4 + b
-5 = 4 + b
b = -5 - 4
b = -9
For a = 5:
5(5) = 4 + b
25 = 4 + b
b = 25 - 4
b = 21
For a = 9:
5(9) = 4 + b
45 = 4 + b
b = 45 - 4
b = 41
So, the values of a and b that make x = -2 are:
a = -9, b = -49
a = -5, b = -29
a = -1, b = -9
a = 5, b = 21
a = 9, b = 41
Substituting x = -2 into the equation, we have:
a(3 - (-2)) = -2(-2) + b
Simplifying the equation:
a(3 + 2) = 4 + b
a(5) = 4 + b
Now we have the equation:
5a = 4 + b
Since we don't have any additional information or constraints, there can be multiple values of a and b that satisfy this equation. We can choose any arbitrary values for a, and then solve for the corresponding value of b.
Let's choose a = 1:
5(1) = 4 + b
5 = 4 + b
Subtracting 4 from both sides of the equation:
5 - 4 = b
1 = b
So, one possible solution is a = 1 and b = 1.
However, there can be other valid solutions as well. For example, if we choose a = 2, we'll get:
5(2) = 4 + b
10 = 4 + b
Subtracting 4 from both sides:
10 - 4 = b
6 = b
So, another possible solution is a = 2 and b = 6.
In summary, there can be multiple values of a and b that make x = -2 in the equation a(3-x) = -2x + b. Some possible solutions are a = 1 and b = 1, and a = 2 and b = 6.