Question

make l the subject of the formula

t = 2π√(l/g)

Answer 1

t = 2π√(l/g)

t/(2π) = √(l/g)
t^2/(4π^2) = l/g
Now finish it off

Answer 2

[AI-generated answer — Explain Bot]

To make "l" the subject of the formula, we need to isolate it on one side of the equation.

Given formula: t = 2π√(l/g)

Step 1: Square both sides of the equation to eliminate the square root:
t^2 = (2π√(l/g))^2

Step 2: Simplify the right side of the equation:
t^2 = 4π^2(l/g)

Step 3: Multiply both sides of the equation by (g/4π^2):
t^2 × (g/4π^2) = (g/4π^2) × 4π^2(l/g)

This simplification cancels out the π^2 and g terms on the right side:

t^2 × (g/4π^2) = l

Therefore, the formula with "l" as the subject is:

l = (t^2 × g) / (4π^2)

To find the value of "l", you need to know the values of "t" (time) and "g" (acceleration due to gravity), and then substitute them into the formula.