I start with any 2 consecutive integers. I square each of them, then I add the 2 squares together. Construct an algebraic expression showing this
To construct an algebraic expression for the given problem, let's start by assigning variables to the two consecutive integers. Let's say the first integer is represented by "x," and the second consecutive integer is "x + 1."
Next, we need to square each of these integers. Squaring "x" would be represented by "x^2," and squaring "x + 1" would be "(x + 1)^2."
Now, we can add these two squares together. The algebraic expression for adding the squares would be:
x^2 + (x + 1)^2
This represents the sum of the squares of the two consecutive integers.
To construct an algebraic expression for the given scenario, let's break it down step by step.
Step 1: Start with any two consecutive integers.
Let's assume one integer is x. Since the integers are consecutive, the second integer would be x + 1.
Step 2: Square each of the integers.
The square of x is x^2, and the square of x + 1 is (x + 1)^2.
Step 3: Add the two squares together.
Adding x^2 and (x + 1)^2 gives us the expression x^2 + (x + 1)^2.
Therefore, the algebraic expression for the given scenario is:
x^2 + (x + 1)^2
integers: x and x+1
squares: x^2 and (x+1)^2
now just finish it off.