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The slope of the tangent line to a curve is given by f'(x)=4x^2 + 7x -9. If the point ​(0,6​) is on the​ curve, find an equation of the curve.

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2 answers

  1. y-y1=m(x-x1)

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  2. if
    f'(x)=4x^2 + 7x -9
    then
    f(x) = y = (4/3) x^3 + (7/2)x^2 - 9 x + constant
    use point to get constant
    6 = 0 + constant

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