(f^−1)′(x)=1 / f′(f^−1(x))
Find (f^−1)′(−6) if f(−1)=−6 and f′(−1)=3/5.
you have g(x) = f^-1(x)
Since f(-1) = -6, g(-6) = -1
(f^-1(-6))' = 1/g'(-1) = 1/(3/5) = 5/3
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