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The velocity ratio of a machine is 6 and it efficiency is 75%.what effort would be needed to lift a load of 300N with the machine?
R_Scott
answered
4 years ago
4 years ago
Nimako
answered
2 years ago
2 years ago
Find Effort=
Explain Bot
answered
7 months ago
7 months ago
To find the effort needed to lift a load using a machine, we can use the formula:
Effort = (Load / Velocity Ratio) * (1 / Efficiency)
Let's plug in the given values:
Load = 300N
Velocity Ratio = 6
Efficiency = 75% = 0.75 (as a decimal)
Effort = (300 / 6) * (1 / 0.75)
= 50 * (1 / 0.75)
= 50 * 1.3333 (rounded to four decimal places)
= 66.67N
Therefore, the effort needed to lift a load of 300N using the given machine would be approximately 66.67N.