Question

Prove:

1^2+2^2+3^2+...+n^2= [n(n+1)(2n+1)]/6

wher: n is natural number

Answer 1

In google paste:

1^2+2^2+3^2+...+n^2= [n(n+1)(2n+1)]/6

when you see list of results go on:

h t t p s://socratic.o r g › questions › can-you-prove-that-1...

You will see solution with explanation.