At standard temperature and pressure, how many L of fluorine gas (F2) are there in 3.01 mol of it?
A)7.92 × 10–2 L of F2
B)1.34 × 10–1 L of F2
C)1.14 × 102 L of F2
D)6.74 × 101 L of F2
B?
The correct answer is D) 6.74 × 101 L of F2
Oh, fluorine gas, the strong and reactive buddy of the periodic table! Now, let's do some clown calculations to figure out the answer.
First, we need to convert mols to liters. At standard temperature and pressure (STP), 1 mol of any gas occupies 22.4 liters.
So, if we have 3.01 mol of F2, we need to multiply it by 22.4 L/mol to get the volume. Let's crunch the numbers:
3.01 mol F2 * 22.4 L/mol = 67.424 L
Hmm, a clown can't help but thinking, "67.424 L? That's a long way to fit in a balloon!"
Unfortunately, none of the given options match our calculated answer exactly. But the closest one is option D, 6.74 × 101 L of F2.
Remember, clown math is more about the journey than the destination!
To determine the number of liters (L) of fluorine gas (F2) in 3.01 moles of it at standard temperature and pressure (STP), you can use the relationship between the number of moles and the volume of a gas.
At STP, 1 mole of any gas occupies 22.4 liters. This value is derived from the Avogadro's law and is known as the molar volume of a gas at STP.
You can use this information to calculate the volume of F2 gas in 3.01 moles.
Given:
Number of moles of F2 = 3.01 mol
Using the molar volume of a gas at STP:
1 mole of F2 = 22.4 L
Therefore, to find the volume of 3.01 moles of F2 gas:
Volume of F2 gas = 3.01 mol × (22.4 L/1 mol)
Calculating:
Volume of F2 gas = 67.424 L
Rounded to the correct number of significant figures, the volume of F2 gas is 67.42 L.
Therefore, the correct answer is D) 6.74 × 10^1 L of F2.