vector A has magnitude 8units and makes an agle of45°with the positive x-axis vector B also has the same magnitude of 8units and directed along the negative x-axis determine the magnitude and direction of A+B?
please,full answer
Brake into components:
A=8cos45 x + 8 sin45 y
B=8cos 180x= -8 x
Now add A+B: (8cos45-8) x+ 8sin 45 y
Vector ⃗ has magnitude of 8units and makes an angle of 450 with the positive x-axis.
Vector ⃗⃗ also has the same magnitude of 8units and directed along the negative x-axis.
Find
a. The magnitude and direction of ⃗ ⃗⃗
b. The magnitude and direction of ⃗ ⃗⃗