Make B,L the subject of the formula when P=2(L+B)
P=2(L+B)
P = 2L + 2B
P - 2L = 2B
B = (P-2L)/2
Do the same steps to get L
Sure!
Let's solve the equation P = 2(L + B) for L.
First, let's distribute the 2:
P = 2L + 2B
Now, let's isolate the term with L:
2L = P - 2B
To make L the subject, we need to divide both sides of the equation by 2:
L = (P - 2B) / 2
So, when P = 2(L + B), L can be written as:
L = (P - 2B) / 2
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To make B and L the subject of the formula when P = 2(L + B), we need to rearrange the equation to isolate either B or L.
Step 1: Distribute the 2 on the right side of the equation:
P = 2L + 2B
Step 2: Move the 2L term to the left side of the equation by subtracting 2L from both sides:
P - 2L = 2B
Step 3: Divide both sides of the equation by 2 to solve for B:
B = (P - 2L) / 2
Now we have B as the subject of the formula. To make L the subject of the formula, we need to rearrange the equation again.
Step 1: Distribute the 2 on the right side of the equation:
P = 2L + 2B
Step 2: Move the 2B term to the left side of the equation by subtracting 2B from both sides:
P - 2B = 2L
Step 3: Divide both sides of the equation by 2 to solve for L:
L = (P - 2B) / 2
Now we have L as the subject of the formula.