Moles HCl=MolesAmmonia
Molarity*Volume=
.8*.0184= ?? Moles
Molar concentrationAmmonia = above moles/.005
If 18.4mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of a household ammonia solution, what is the molar concentration of the ammonia?
Molarity*Volume=
.8*.0184= ?? Moles
Molar concentrationAmmonia = above moles/.005
Sorry about that
The chemical 5-amino-2,3-dihydro-1,4-phthalazinedione, better known as luminol, is used by forensic scientists in analyzing crime scenes for the presence of washed-away blood. Luminol is so sensitive that it can detect blood that has been diluted 10,000 times. A basic solution of luminol is often sprayed onto surfaces that are suspected of containing minute amounts of blood.
Luminol has a molecular weight of 177g/mol
The forensic technician at a crime scene has just prepared a luminol stock solution by adding 14.0 of luminol into a total volume of 75.0 mL of H2O.
1. What is the molarity of the stock solution of luminol?
ANSWER:molarity of luminol solution =1.05 M
2.Before investigating the scene, the technician must dilute the luminol solution to a concentration of 6.00Γ10β2 . The diluted solution is then placed in a spray bottle for application on the desired surfaces.
How many moles of luminol are present in 2.00 L of the diluted spray?
ANSWER: moles of luminol =0.120
3.What volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B)?
Answer: needs to be in mL and i cant figure it out. Can someone please help
The balanced equation for the reaction is:
NH3 + HCl -> NH4Cl
From the equation, we can see that 1 mole of NH3 reacts with 1 mole of HCl to form 1 mole of NH4Cl.
Given the volume and molar concentration of the HCl solution, we can calculate the number of moles of HCl:
moles of HCl = volume of HCl solution (in L) Γ molar concentration of HCl
Converting the volume of HCl solution to liters:
volume of HCl solution = 18.4 mL = 18.4 Γ 10^(-3) L
Substituting the values:
moles of HCl = (18.4 Γ 10^(-3) L) Γ (0.800 mol/L)
Next, we need to find the number of moles of NH3 that reacted with the HCl. According to the balanced equation, the molar ratio between NH3 and HCl is 1:1.
Therefore, the number of moles of NH3 reacted = moles of HCl
Now, we can calculate the molar concentration of the NH3 solution:
molar concentration of NH3 = moles of NH3 reacted / volume of NH3 solution (in L)
Given the volume of the NH3 solution:
volume of NH3 solution = 5.00 mL = 5.00 Γ 10^(-3) L
Substituting the values:
molar concentration of NH3 = moles of NH3 reacted / (5.00 Γ 10^(-3) L)
Finally, substitute the value of moles of NH3 reacted (which is equal to the moles of HCl calculated earlier) and solve for the molar concentration of NH3.