Question

A metal block of mass 5kg lies on a rough horizontal platform. If a horizontal force of 8 N applied to the block through its center of mass just slides the block on the platform, then the coefficient of limiting friction between the block and the platform is: A 0.16 B 0.63 C 0.80 D 1.6 E 2.00.

Answer 1

coefficent= friction/weight= 8/(5*9.8)= ...

Answer 2

M*g = 5*9.8 = 49 N. = Wt. of block = Normal force,

8-u*49 = 5*0.
u = coefficient of friction = 8/49 = 0.16.

Answer 3

answer question which above

Answer 4

The answer is A: 0.16

Answer 5

Yes it is A.0.16

Coefficient of friction =force/mass*acceleration due to gravity. That is 8/5*10 =O.16

Answer 6

A METAL BLOCK OF MASS IS 5KG LIES

Answer 7

Yes it is 0.16

Answer 8

Yes it is 0.16

Answer 9

The answer is 0.16

Answer 10

Solution

F/mg
8/5*10=0.16

Answer 11

Yes it is 0.16

F-uR
8-u*5*10
U-0.16