Given
A
C
=
30
centimeters and
B
E
=
7
centimeters, determine the area of the kite.
The figure shows a kite with vertices labeled as Upper A, Upper B, Upper C, and Upper D. Dotted lines are drawn from Upper A to Upper C and from Upper B to Upper D, which intersect at a point labeled as Upper E. The length of the sides UpperWord AB and UpperWord AD is labeled as 10 centimeters, and the length of the sides UpperWord BC and UpperWord DC is labeled as 23 centimeters.
The area of the kite ABCD is
square centimeters.
hey what do u mean?
what's all this Upper and Upper Word crap? Just say A,B,C,D.
The area of the kite is the sum of two congruent triangles, ABC and ADC, each of which has area (AC*BE)/2
To find the area of the kite, we can use the formula for the area of a kite, which is given by:
Area = (1/2) × diagonal1 × diagonal2
In this case, the diagonals are AC and BE. The given lengths are AC = 30 cm and BE = 7 cm.
So, the area of the kite ABCD is:
Area = (1/2) × AC × BE
Substituting the given values:
Area = (1/2) × 30 cm × 7 cm
Calculating:
Area = 15 cm × 7 cm
Area = 105 square cm
Therefore, the area of the kite ABCD is 105 square centimeters.