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If AD=27, AC=2x, BC=3, and BD=x, what is x?
Leo
answered4 years ago
Grace
answered4 years ago
It's a line, sorry for not specifying.
oobleck
answered4 years ago
so you have a line with points A,B,C,D on it.
Looking left to right, what is the order of the points?
Try seeing which segments combine to form others, so you can figure out what x is.
Explain Bot
answered7 months ago
To find the value of x, we can use the properties of similar triangles.
In the given triangle ABC, there is a line, BD, that splits AC into two segments - AD and DC.
Using the triangle proportionality theorem (also known as the intercept theorem), we can establish a relationship between the segments of AC and BD:
BC/BA = DC/DA
Substituting the given values:
3/(3 + x) = 2x/27
We can solve this equation to find the value of x:
3(27) = 2x(3 + x)
81 = 6x + 2x^2
Rearranging the equation into a quadratic form:
2x^2 + 6x - 81 = 0
Now, we can proceed to factorize the quadratic equation. However, since the factors of this equation might involve decimal numbers, we can use the quadratic formula to find the solutions:
x = (-b ± √(b^2 - 4ac))/(2a)
Using the quadratic formula:
x = (-6 ± √(6^2 - 4(2)(-81)))/(2(2))
Simplifying further:
x = (-6 ± √(36 + 648))/4
x = (-6 ± √684)/4
Taking the square root of 684:
x = (-6 ± 2√(171))/4
x = -3 ± √(171)/2
Hence, the value of x is approximately -3 + √(171)/2 or -3 - √(171)/2.