A woman is 43 years old, and her daughter is 15 years old. How many years will it be before the woman’s age is just twice her daughter’s?
W = 43 = present woman’s age
D = 15 = present daugter’s age
W - D = 43 - 15
W - D = 28
Add D to both sides
W = D + 28
Woman is 28 yrs older of daugter.
Woman will be twice older of daugter when:
W = 2 D
So:
W = 2 D
Replace W = D + 28 in this equation
D + 28 = 2 D
Subtract D to both sides
28 = D
D = 28
Woman will be twice older of daugter when daugter be 28 yrs old.
Present daugter’s age = 15
28 - 15 = 13
After 13 yrs woman will be twice older of her daughter.
Proof:
After 13 yrs woman will be 43 + 13 = 56 yrs old
Daughter will be 15 + 13 = 28 yrs old
56 / 28 = 2
Ah, the age-old math problem! Let me put on my thinking cap.
Okay, here we go. So currently, the woman is 43 and her daughter is 15. Let's assume it will take 'x' years for the woman's age to be twice her daughter's age.
In 'x' years, the woman will be 43 + x years old, and her daughter will be 15 + x years old.
According to the problem, the woman's age will be twice her daughter's age, so we can write this equation:
43 + x = 2(15 + x)
Now let's solve it step by step.
43 + x = 30 + 2x (Using the distributive property)
43 - 30 = 2x - x (Subtracting 'x' from both sides)
13 = x
So, it will take 13 years before the woman's age is just twice her daughter's age.
I know math isn't the funniest subject, but hey, I tried to bring a little humor to the equation!
To find out how many years it will be before the woman's age is twice her daughter's, we need to set up an equation using variables.
Let's assume that after x years, the woman's age will be twice her daughter's. If the woman is currently 43 years old and her daughter is 15 years old, after x years, the woman's age will be 43 + x, and the daughter's age will be 15 + x.
Therefore, we can write the equation as:
43 + x = 2(15 + x)
Now, let's solve the equation to find the value of x.
Distribute the 2 on the right side of the equation:
43 + x = 30 + 2x
Now, subtract x from both sides of the equation:
43 = 30 + x
Next, subtract 30 from both sides:
43 - 30 = x
13 = x
Therefore, it will be 13 years before the woman's age is just twice her daughter's.