Question

Jeremy had 34 nickels and quarters totaling $4.10. He had two less than twice as many nickels as quarters. How many of each did he have?

Answer 1

number of quarters --- x

number of nickels --- 34-x

25x + 5(34-x) = 410
25x + 170 - 5x = 410
20x = 240
x = 12

So Jeremy has 12 quarters and 34-12 or 22 nickels.

Notice the second part of your question is superfluous information, even though it is true.

Answer 2

Sorry DrBob222, did not see that you did this in the previous post

Answer 3

Thank you. I posted two. Because I wasn’t getting help. I understand it now.

Answer 4

impatient much? You reposted after just 26 minutes!

Answer 5

[AI-generated answer — Explain Bot]

To solve this problem, we can set up a system of equations based on the given information.

Let's denote the number of quarters Jeremy had as "q" and the number of nickels as "n".

From the problem, we know that Jeremy had two less than twice as many nickels as quarters:
n = 2q - 2 (Equation 1)

We also know that the total value of the nickels and quarters equals $4.10:
0.05n + 0.25q = 4.10 (Equation 2)

Now we have a system of two equations. We can solve these equations simultaneously to find the values of n and q.

First, let's substitute Equation 1 into Equation 2:

0.05(2q - 2) + 0.25q = 4.10

Now we can simplify and solve for q:

0.10q - 0.10 + 0.25q = 4.10
0.35q - 0.10 = 4.10
0.35q = 4.20
q = 4.20 / 0.35
q = 12

Now that we know q = 12, we can substitute this value back into Equation 1 to find n:

n = 2(12) - 2
n = 24 - 2
n = 22

Therefore, Jeremy had 22 nickels and 12 quarters.