how to calculate the mass and volume of oxygen released when 29,4 g potassium chlorate decomposes to form potassium chloride and oxygen?

how many moles of KClO3 in 29,4 grams?

Look at the balanced equation to see how many moles of O2 are produced by each mole of KClO3.
Convert that to grams of O2
For volume, recall that 1 mole occupies 22,4 L at STP.

The equation is

2KClO3 ==> 2KCl + 3O2

To calculate the mass and volume of oxygen released when potassium chlorate decomposes, you need to understand the stoichiometry of the reaction. The balanced equation for the decomposition of potassium chlorate (KClO3) is:

2KClO3 → 2KCl + 3O2

From this equation, you can see that for every 2 moles of KClO3 that decompose, you get 3 moles of O2.

To calculate the mass and volume of oxygen released, follow these steps:

Step 1: Determine the molar mass of potassium chlorate (KClO3).
- The atomic masses of potassium (K), chlorine (Cl), and oxygen (O) are approximately 39.10 g/mol, 35.45 g/mol, and 16.00 g/mol, respectively.
- The molar mass of KClO3 can be calculated as follows:
Molar mass of KClO3 = (1 * K) + (1 * Cl) + (3 * O)
= (1 * 39.10) + (1 * 35.45) + (3 * 16.00)
= 122.55 g/mol

Step 2: Calculate the number of moles of potassium chlorate (KClO3) present in 29.4 g.
- Use the formula:
Moles = Mass / Molar mass
Moles of KClO3 = 29.4 g / 122.55 g/mol

Step 3: Determine the number of moles of oxygen released.
- Since the stoichiometry of the reaction is 2:3 for KClO3 to O2, the number of moles of O2 can be calculated using the ratio:
Moles of O2 = (3/2) * Moles of KClO3

Step 4: Calculate the mass of oxygen released.
- Use the formula:
Mass = Moles * Molar mass
Mass of O2 = Moles of O2 * Molar mass of O2
= Moles of O2 * 32.00 g/mol

Step 5: Calculate the volume of oxygen released at standard temperature and pressure (STP).
- At STP, 1 mole of any gas occupies 22.4 L.
- Use the formula:
Volume = Moles * 22.4 L/mol (at STP)
Volume of O2 = Moles of O2 * 22.4 L/mol

By following these steps, you can calculate the mass and volume of oxygen released when 29.4 g of potassium chlorate decomposes.