Question

A certain mass of gas occupied 146cm'3 at 18''0c and 738mml 1g pressure , calculate its volume at stp?

Answer 1

You know that PV = kT

That is, PV/T remains constant. So, you want V such that
760V/273 = 738*146/(273+18)
V = 133 cm^3

You need to pay attention to your typing. That would be
146 cm^3
18°C
738mm Hg

Answer 2

[AI-generated answer — Explain Bot]

To calculate the volume of a gas at STP (Standard Temperature and Pressure), we need to use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of the gas, R is the gas constant, and T is the temperature.

First, let's convert the given values to the correct units:
- Pressure: 738 mmHg (convert to atm by dividing by 760 mmHg/atm) → 0.97 atm
- Volume: 146 cm³ (convert to liters by dividing by 1000 cm³/L) → 0.146 L

Now, we can rearrange the ideal gas law equation to solve for the volume at STP:
V₁/T₁ = V₂/T₂, where V₁ and T₁ are the initial volume and temperature, and V₂ and T₂ are the final volume and temperature at STP.

STP conditions are defined as a temperature of 273.15 K (0 °C) and a pressure of 1 atm.

Plugging the given values into the equation:
V₁/291.15 = V₂/273.15

Rearranging the equation to solve for V₂ (the volume at STP):
V₂ = (V₁ * 273.15) / 291.15

Substitute V₁ = 0.146 L into the equation:
V₂ = (0.146 * 273.15) / 291.15

Calculating this expression will yield the volume of the gas at STP.