the angle of elevation of the top of a radio mast from a point due east of it and 96m away from its base is 30degrees. from another point due west of the mast, the angle of elevation of the top is 60degrees. calculate the distance of the second point from the base of the mast

Draw a diagram. If the height is h, then on the east side

h/96 = tan30°
On the west side, if the observation point is at distance x, then
h/x = tan60°

So, x = (96 tan30°)/(tan60°) = 32m

Pls help me draw the diagram

Please the diagram

d workings

Thank u so much

But where's the diagram??????

Please the diagram

Pls d diagram

Thank you but where is the diagram

No diagram👎

Please Where Is The Diagram And I Dont understand The Calculation

Please draw the diagram

Pls the diagram and the calculations are not clear to me pls is it possible to make calculations more elaborate

Sure, I apologize for the confusion. Here's a diagram and further elaboration on the calculations:

Let's denote the base of the radio mast as point B, the observation point due east as point E, the observation point due west as point W, and the top of the mast as point T.

Based on the information given, we can draw the following diagram:

```
T
|
|
| h
|
|
|
E --------- B --------- W
96m
```

We can see that the angle of elevation from E is 30°, which means that the triangle EBT is a right-angled triangle with angle BTE = 30°. We can use the tangent function to find the value of h:

tan(30°) = h/96
h = 96 * tan(30°)
h ≈ 55.4m

Now let's consider the angle of elevation from W, which is 60°. This means that the triangle BTW is also a right-angled triangle, with angle BTW = 60°. We can use the tangent function again to find the distance x between W and the base of the mast B:

tan(60°) = h/x
x = h/tan(60°)
x = 55.4m / √3
x ≈ 32m

Therefore, the distance of the second point from the base of the mast is approximately 32m.

I hope this helps! Please let me know if you have any further questions or concerns.