a sulphuric acid solution contains 66% H2SO4 by weight and has the density of 1.58 gmL^-1 . how many moles of the acid are present in 1.00L of the solution. Molar mass for H2SO4 is 98.09 gmol^-1

1.58 g/mL x 1000 mL x 0.66 x (1 mol/98.09 g) = ? mols.

Well, I'm glad you asked. Let's break it down, shall we?

First, we need to find the mass of the solution. Since we're dealing with 1.00L of the solution and the density is 1.58 g/mL, we can multiply the density by the volume to get the mass.

1.58 g/mL * 1.00 L = 1.58 g

Next, we need to find the actual mass of the acid in the solution. Since the solution is 66% H2SO4 by weight, we can multiply the mass of the solution by 66% (or 0.66).

1.58 g * 0.66 = 1.04 g

Now, it's time to convert the mass of the acid to moles. We can do this by dividing the mass by the molar mass of H2SO4 (98.09 g/mol).

1.04 g ÷ 98.09 g/mol = 0.0106 mol

So, there you have it. In 1.00L of the sulphuric acid solution, there are approximately 0.0106 moles of H2SO4.

To solve this problem, we can follow these steps:

Step 1: Calculate the mass of the solution.
Given density of the solution = 1.58 g/mL
Given volume of the solution = 1.00 L

Mass = density * volume
Mass = 1.58 g/mL * 1000 mL = 1580 g

Step 2: Calculate the mass of H2SO4 in the solution.
Given percentage of H2SO4 by weight = 66%
Mass of H2SO4 = (66/100) * 1580 g = 1042.8 g

Step 3: Calculate the number of moles of H2SO4.
Given molar mass of H2SO4 = 98.09 g/mol

Number of moles = mass / molar mass
Number of moles = 1042.8 g / 98.09 g/mol ≈ 10.63 mol

Therefore, there are approximately 10.63 moles of sulphuric acid present in 1.00L of the solution.

To find the number of moles of H2SO4 in the given solution, you first need to calculate the mass of H2SO4 present in 1.00L of the solution. Here's how you can do it step by step:

Step 1: Calculate the mass of 1.00L of the solution.
Given density of the solution = 1.58 g/mL
Volume of the solution = 1.00 L

Mass of the solution = density × volume
Mass of the solution = 1.58 g/mL × 1.00 L = 1.58 g

Step 2: Calculate the mass of H2SO4 in the solution.
Percentage of H2SO4 by weight = 66%
Mass of H2SO4 in the solution = Percentage of H2SO4 × Mass of the solution

Mass of H2SO4 = 66% × 1.58 g = 1.0408 g

Step 3: Calculate the number of moles of H2SO4.
Molar mass of H2SO4 = 98.09 g/mol
Number of moles of H2SO4 = Mass of H2SO4 / Molar mass of H2SO4

Number of moles of H2SO4 = 1.0408 g / 98.09 g/mol ≈ 0.0106 mol

Therefore, there are approximately 0.0106 moles of H2SO4 present in 1.00L of the given solution.