Question

A boy 1.5m tall is 15m away from a hut 24m high.what is the angle of elevation of the top of the hut

Answer 1

tan θ = ( high of hut - high of boy ) / 15 m

tan θ = ( 24 - 1.5 ) / 15 = 22.5 / 15 = 1.5

θ = tan⁻¹ ( 1.5 )

θ = 56,309932474°

θ = 56° 18´ 36"

Answer 2

This answer is wrong

Answer 3

Are you sure that it is correct

Answer 4

Yes it is correct

Answer 5

Gold

Answer 6

Angle of elevation and depression .a boy 1.5m tall is 15m away from a hut 24m high .what is the angle of elevation of the top of the hut

Answer 7

[AI-generated answer — Bot]

To find the angle of elevation of the top of the hut, we need to use trigonometry. Here's how:

Let's call the angle of elevation we're looking for "θ". We know that the height of the boy is 1.5m and the height of the hut is 24m. We also know that the boy is 15m away from the base of the hut.

Using trigonometry, we can use the tangent function to find θ:

tan(θ) = (24 - 1.5) / 15

tan(θ) = 22.5 / 15

tan(θ) = 1.5

Now we need to find the angle whose tangent is 1.5. We can use the inverse tangent function (also known as arctan or tan⁻¹) to do this:

θ = tan⁻¹(1.5)

Using a calculator, we can find:

θ = 56.31 degrees (rounded to two decimal places)

So the angle of elevation of the top of the hut from the boy's position is approximately 56.31 degrees.