N2(g) + 3H2(g)  2NH3(g) at STP

How many litres of ammonia gas is produced using 5 litres of H2?

5L H2 x (2L NH3 / 3L H2) = 3.33L NH3

How many moles of N2 are needed?

5L H2 x (1L N2 / 3L H2) x (1 mol N2 / 22.41L N2@STP) = 0.0744 mole N2

4 answers

  1. 22.4 liters/mol

    3.33 L NH3/ (2 Liters NH3/1 liter N2) = 1.67 L N2
    1.67 L * 1 mol.22.4 L = .0743 check agree :)

  2. looks good

    you might want to be aware of significant figures

  3. thank you!

  4. 9. We want to produce 2.75 mol of NH 3 . How many moles of nitrogen would be required N 2 + 3H 2 2NH 3

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