a runner jogs 12 km north then turns and runs 16 km east in three hours.what is his displacement
a runner jogs 12 km north then turns and runs 16 km east in three hours.
A) what is his displacement?
B) calculate his average speed.
C) calculate his average velocity ( including the direction).
A.20 km due to north -east.because he first go to north and second turn to east.i think he make perpendicular logicaly.SO,YOU CAN USE PHAYTAGORAS THEREOM TO FIND THE ANSWER. BFORE YOU DO, YOU SHOULD UNDERSTAND LOGICALLY.HE GOT DIRECTION BETWEEN NORTH AND SOUTH,THAT IS NORTH-EAST DIRECTION
B.28/3 km/hr.because he doesn,t need direction simply add all distance then divide by all taken time. FORMULA=TOTAL DISTANCE DIVIDE BY TOTAL TIME
C.20/3 km/hr north-east direction. FORMULA=TOTAL DISPLACEMENT DIVIDE BY TOTAL TIME.SO,THE DIRECTION IS NORTH-EAST DIRECTION.
A) displacement is the distance (and direction) from the starting point to the finishing point ... it is a vector quantity
B) the average speed is the actual distance that he ran, divided by the time it took ... it is a scalar quantity
C) the average velocity is the displacement divided by the time ... it is a vector quantity
runner jogs 12 km north then turns and
runs 16 km east in three hours.
A) what is his displacement?
B) calculate his average speed.
C) calculate his average velocity
( including the direction).
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Student
answers
answer
A20km
Caculate His Average Speed$ Average Velocity Incuding The Direction
12 km runs 16 km
Deribe
Arunner jogs12km norththe turns 16 km east in 3 hour find
A distance
B Displacement
C average of speed
D average of velocity
make
A 28kmh
B 400 km
C 9.333..
D 2.22222km2