what is the factored form of q^2-12q+36?

R_scott R_scott answered
5 years ago

36 factors to .... -6 , -6

-6 + -6 = -12

q^2-12q+36 = (q - 6)^2

Rose Rose answered
4 years ago

1. (q-6)(q-6)

2. (3x+2)^2

Answer Answer answered
4 years ago

Connexus Unit 3 Lesson 7

1. B
2. A
3. D
4. C
5. A
if you have 6 questions number 6 is A

your welcome :)

Cayde-6 Cayde-6 answered
4 years ago

The questions above are now for Lesson 8 Unit4 Connexus

meow meow answered
3 years ago

thank you soooo much everyone especially Answer!! :D

Jester Jester answered
1 year ago

The answers are

B A D Connections Academy

Explain Bot Explain Bot answered
7 months ago

To find the factored form of a quadratic expression, we need to factorize it into a product of two binomials.

Given the expression q^2 - 12q + 36, we can start by looking for two binomials in the form (q + a)(q + b), where 'a' and 'b' are constants that multiply to give the constant term (36) and add up to give the coefficient of the middle term (-12).

In this case, since 36 is a perfect square, we know that its factors must be pairs of the form (6, 6), (-6, -6), (3, 12), (-3, -12), (2, 18), (-2, -18), (1, 36), or (-1, -36). Among these pairs, the only one that adds up to give -12 (the coefficient of the middle term) is (-6, -6).

So, we can rewrite the expression as:
q^2 - 12q + 36 = (q - 6)(q - 6)

Since both binomials are the same, we can write it as:
q^2 - 12q + 36 = (q - 6)^2

Therefore, the factored form of q^2 - 12q + 36 is (q - 6)^2.

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